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Value of n^5/n!=52e. how this value obtainned. Could any of you tell me the method?


Thankyou.......

3 years ago

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Answers : (1)

                                        

This is a TRANSCENDENTAL equation. There is no method. The only way to solve the equation is trial and error.

3 years ago

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Why is equation (1) not a polynomial equation and equation (2) not a polynomial in y? (1) dy/dx + sin(dy/dx) = 0 (2) (dy/dx) 2 +(dy/dx) - sin 2 y = 0
 
 
Being a equation and a polynomial equation is very different. Functions like sinx, lnx, e x are not considered polynomial quations. They are transcental functions.
 
Nibir Pawan Das 11 months ago
 
@Yugabrat sinx=0 is also a equation..
 
Shibashis Mallik 11 months ago
 
As sin is present...
 
Yugabrat Gogoi 11 months ago
Q .FIND THE DOMAIN OF THE FUNCTION WHOSE PIC IS ATTACHED-
 
 
Dear student, Pls send the pic of the question again. I cann’t see any pic attached. Thanks,...
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Nishant Vora 10 months ago
 
Dear student, Regards
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Sumit Majumdar 10 months ago
 
i have put up the same question with the pic attached
 
Bharat Makkar 10 months ago
Let f : A-> A where A = { 1, 2, 3, 4, 5} such that ff(x) = x . How many such functions are possible
 
 
First note that the function is injective: f(x) = f(y) implies f(f(x)) = f(f(y)) which yields x = y. We say that a number x is fixed by f if f(x) = x. Now, if f(a) = b, with a and b...
 
mycroft holmes 11 months ago
 
In general the real functions which satisfies the condition that fof(x) = x are (i) f(x) = a – x where a is any real no. (ii) f(x) = x But here, f: A → A is the function which should...
 
Y RAJYALAKSHMI 11 months ago
 
Pl. ignore this solution – it is incomplete
 
Y RAJYALAKSHMI 11 months ago
if the light velocity is a vector quantity, why vector addition cannot be applied to it?
 
 
Dear student, Velocity of light like other velocities, is a vector quantity. So, in vector addition, veloicty of light is going to be added vectorially. Moreover, the velocity of light has a...
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Sumit Majumdar 11 months ago
If A,B,C are the angles of triangle ABC and tanA,tanb,tanc are the roots of the equation x^​4-​3​x^​3+​3x^​2+​2​x+​5 then find the 4 th root of the equation.
 
 
use the formula alpha +beta+gama+delta =-(-3) and again uing these actors find the value
 
Karthik Pasupulatei 14 days ago
 
 
Lab Bhattacharjee 19 days ago
File attached.
 
 
In vector form, a + b = c and DB = a – b DB.AB = (a-b).a = a 2 – a.b
  img
Abhishek Kumar 4 months ago
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