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Tushar Watts Grade: 12
        

Show that the min value of 4x2+4x |sin@| -  cos2@  is -1

7 years ago

Answers : (1)

Pratham Ashish
17 Points
										

hi,


p = 4x2+4x |sin@| -  cos2@  is -1


   = 4x2+4x |sin@| -1 + sin2@                 (  sin2@  = |sin@| ^2 )


   =4x2+4x |sin@| + |sin@| ^2 - 1


   = ( 2x + |sin@| )^2  -1


 give min . value when the squre part will be equal to zero.


 hence min. value = -1 

7 years ago
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