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Saneet Satish Agrawal Grade: 12
        

Find the maximum value of  x2y subject to the constraint:


x+y+(2x2+2xy+3y2)1/2 =k     where k is a constant and x,y>=0

8 years ago

Answers : (1)

askIITIians Expert
21 Points
										

 


Given,


x+y+(2x2 + 2xy + 3y2 )1/2 = k


x,y >= 0


Dear Student,


First write the above relation seperating y on one side and then substituting it in the equation.


z = x2y


1. Find dy/dx


2. Equate it to zero and get the value of x.


3. Then find d2y/dx2 & substitute the values of x from Step (2) in d2y/dx2  


4. If d2y/dx2   is -ve, it is maxima.


5. Substitute that value of y in the function, f = x2 y , you get the maximum value.


 


 

8 years ago
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