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`        Let f(x) = (2x-pie) 3 +2x - cosx. Then show that d[ f -1 (x)] / dx  at x=pie/2 is 1/3.`
8 years ago

Ramesh V
70 Points
```										(1) It's "Pi". and  Pi is not  22/7
first find df(x) / dx.

df(x)/dx = 3(2x - pi)2 * 2 + 2 + sin(x)
=6(2x - pi)2  + 2 + sin(x)

Let x = pi/2 , we  get:  0 + 2 + 1 = 3

So the answer for df-1(x)/dx  i.e., 1/[df(x)/dx]   is : 1/3
--
Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and
we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.

Regards,
Naga Ramesh
IIT Kgp - 2005 batch
```
8 years ago
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