Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 320 off


Let f : (0 , pie) is defined to R by f(x) = max { sin2x, cos2x}. then show that the set of points of which f(x) has a local maxiam or minima is equlas to { pie/8 , pie/4 , 5 pie/8 } .

7 years ago


Answers : (2)


From the figure , the curve f(x) is shown in black bold line

the local minima is at : Pi/8 , 5Pi/8

and local maxima at : Pi/4


Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult to understand - post it here and

we will get you the answer and detailed solution very quickly.We are all IITians and here to help you in your IIT JEE preparation. All the best.


Naga Ramesh

IIT Kgp - 2005 batch

7 years ago

period of cos2x,sin2x is pie

we will redefine the function given

now in(0,pie/8) cos2x.>sin2x , in (pie/8 to 5pie/8) sin2x>cos2x and in ( 5pie/8 to pie)again cos2x>sin2x (by comparing graph)

sof(x) = cos2x.  (0,pie/8)

               sin2x    (pie/8 to 5pie/8)

               cos2x   ( 5pie/8 to pie)

        now u can get it by drawing the graph

note : pie is not the answer because pie is the last point of the fonction so it is the global maxima not the local maxima.

7 years ago

Post Your Answer

Other Related Questions on Differential Calculus

Question: If xe^(xy) – y = sin^2x, then find dy/dx at x=0.
Given eqn. xe^(xy) – y = sin^2x, Differentiate y w.r.t. x as: (1)e^(xy) + xe^(xy)*[1.y + xdy/dx] – dy/dx = sin2x collect dy/dx, put x = 0: dy/dx = 1 is the answer.
Vikas TU 5 months ago
xe^xy – y = sin^2x ∴ y = xe^xy – sin^2x Differention both sides w.r.t x: dy/dx = (1).(e^xy) + (x).(ye^xy) – 2.sinx.cosx ∴ dy/dx = e^xy + xy.e^xy – 2.sinx.cosx NOTE: Differentiate xe^xy by...
Praneet Debnath 4 months ago
Please my doubt . Also pls suggest any graphical way to solve this out . It's urgent . Thankyou
The Graph of this function can be plotted using online tool Search desmos in google Unfortunately this website does not allow attachments for answers hence cannot post how graph looks like. ...
Ajay 4 months ago
You re welcome neha. Regarding books, Cengage has good reviews online, but I have not personally refered to it so cant comment on sufficiency of that book. I hope cengage book should have...
Ajay 4 months ago
I hope you want to ask why domain of arcsin cannot be greater than 1. by definition of inverse function the the domain of arcsin = range of sin function. Now range of sin function is [-1, 1 ...
Ajay 4 months ago
by solving this problems with clear proof,it is in odinary differential solutions.
If the pair of state lines joining the origin to the point of intersection of the ellipse x²∕𝐲²+y²⁄𝐛²=1 and the line 𝑙𝑥+𝑚𝑦+𝑛=0 are parpandecular to each other then show that...
SAMAUL SK 3 months ago
if a>0 ,b>0 ,c>0 and the maximum value of a(b 2 +c 2 ) +b(c 2 +a 2 ) +c(a 2 +b 2 ) is X abc ,then X is (a) 2 (b) 1 (c)6 (d) 3
From AM-GM inequality with equality when b=c. Repeat this for the other two terms and add and you will get RHS with equality when a=b=c
mycroft holmes 2 months ago
For Maximum value, of a(b 2 +c 2 ) +b(c 2 +a 2 ) +c(a 2 +b 2 ) every term needs to be maximum. = > that is considering a b c be triangle sides with a as hypotenuse for maximum for a(b 2 +c...
Vikas TU 2 months ago
Consider the points A (3, 4) and B (4, 13). If ‘P’ be a point on the line y = x such that PA + PB is minimum, then ‘P’ is. A) (13/7,13/7). B). (23/7,23/7) C) (31/7,31/7). D). (33/7,33/7)
Let P be the point as (x, x). then PA = root((x-3)^2 + (x-4)^2)) and PB = root((x-4)^2 + (x-13)^2) PA + PB => root((x-3)^2 + (x-4)^2)) + root((x-4)^2 + (x-13)^2) Now to minimize it the...
Vikas TU 25 days ago
The minimum value of atan 2 x + cot 2 x equals the maximum value of asin 2 y + bcos 2 y where a and b are grater than 0. Then a/b is (a)2 (b)4 (c)6 (d)8 Please explain fully.
The minimum value is 2√ab but I can not understand how it came?
Mudit 2 months ago
Minimum value of atan 2 x + cot 2 x = > First convert them into sec and cosec. = a(sec^2x – 1) + (cosec^2 – 1) = a(1/cos^^2x – 1) + (1/sin^2x – 1) = 1/sin^2x + a/cos^2x – 2 = 1/(1-cos^2x) + ...
Vikas TU 2 months ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,000 off

Get extra R 320 off

More Questions On Differential Calculus

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details