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ABHISHEK VASHIST Grade: 12th pass
        SIR

Q.PLEASE CAN YOU GIVE ME THE DERIVATIVE OF
1. ROOT SINx
2. (ax + b) to the power n.
6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

1) y = (sinx)1/2


   dy/dx = d/dx[(sinx)1/2]


            = (1/2)(sinx)1/2-1 [d/dx(sinx)]                             ( d/dx(xn) = nxn-1)


            =(1/2)(sinx)-1/2(cosx)                                         (d/dx(sinx) =cosx )


2) y = (ax+b)n


 dy/dx = d/dx(ax+b)n


          =n(ax+b)n-1d/dx(ax+b)


         =n(ax+b)n-1[d/dx(ax) + d/dx(b)]                            (d/dx(constant) = 0)


        =n(ax+b)n-1 [a+0]


        na(ax+b)n-1


 

6 years ago
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