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chanda ranjan Grade: Upto college level
```        1.   if lim x9-a9/x-a =lim (4+x),find all possible values of a.
x->a                 x->5
```
7 years ago

510 Points
```										x9-a9= (x3)3-(a3)3  =(x3-a3)(x6+a6+(ax)3)
=(x-a)(x2+a2+ax)(x6+a6+(ax)3)
after putting this ,expression becomes
lim x->a    (x2+a2+ax)(x6+a6+(ax)3) =  lim x->5  (4+x)
after taking limit
(3a2)(3a6)=9
a8=1
a=-1 or 1 a ns

```
7 years ago
80 Points
```										POSSIBLE VALUE OF A IS +1 OR -1.  BECAUSE FOR FIRST LIMIT THATS GONNA BE 9a8 AND FOR SECOND LIMIT ITS GONNA BE 9.  HENCE

9a8=9

a=+1 AND -1

```
7 years ago
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