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mustafa bandook wala Grade: 12
        

what is the diff. of      sin6x+cos6x/sin3x+cos3x

7 years ago

Answers : (3)

ashish kumar
17 Points
										

 


Dear Mustafa,


Its diferentiation will be : -


( 6cos6x  - 6sin6x ) /(3cos3x - 3sin3x )


or, 2 ( cos6x - sin6x ) / ( cos3x - cos3x )


Thank you.

7 years ago
ashish kumar
17 Points
										




Dear Mustafa,


Its diferentiation will be : -


( 6cos6x  - 6sin6x ) /(3cos3x - 3sin3x )


or, 2 ( cos6x - sin6x ) / ( cos3x - cos3x )


Thank you.

7 years ago
Badiuddin askIITians.ismu Expert
147 Points
										

Hi mustafa


y=(sin6x+cos6x)/(sin3x+cos3x)


dy/dx ={(sin3x+cos3x)(6cos6x-6sin6x)-(3cos3x-3sin3x)(sin6x+cos6x)}/(sin3x+cos3x)


                 


Now simplyfy


dy/dx =(3 cos9x -9sin3x)/ (sin3x+cos3x)2


 





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Badiuddin

7 years ago
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