Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Naina Razdan Grade: 12
```
Let g(x) be the inverse of the function f(x), and f'(x)= 1/1+x3. then g(x) is equal to....
```
7 years ago

## Answers : (1)

Chetan Mandayam Nayakar
312 Points
```										f(x) = ∫1/(1+x3)dx  1/(1+x3) = (x+1)/3 - (x/3)/(((x-0.5)^2) +0.75) +(2/3)/(((x-0.5)^2) +0.75)
= (x+1)/3 - (1/6)(2x-1)/(((x-0.5)^2) +0.75) - (1/2)(((x-0.5)^2) +0.75)
therefore, ∫1/(1+x3)dx  = f(x) = (1/3)ln(x+1) - (1/6)ln(x2-x+1) -(1/√3)arctan((2x-1)/√3)
g(x) = ƒ-1(x) implies that f(g(x))= x
x = (1/3)ln(g(x)+1) - (1/6)ln((g(x))2-x+1) -(1/√3)arctan((2g(x)-1)/√3)
One has to solve this equation in g(x) in order to express g(x) explicitly. It is obvious that this equation cannot be solved.
```
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Differential Calculus

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details