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Could explain theses: Jump Disontinuity, Infinite Discontinuity, Oscillating Discontinuity???
Dear Siddharth,
Consider a function ƒ of real variable x with real values defined in a neighborhood of a point x0. Then three situations are possible in which the function ƒ is discontinuous at a point on the real axis x = x0:
An oscillating discontinuity occurs at a value of x near to which a function refuses to settle down.
Example:
The function y=sin(1/x) has a discontinuity at x = 0 because it is not defined at x = 0. It also has an oscillating discontinuity at x = 0,as here the left hand and right hand limit do not exist.
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Regards,
Askiitians Experts
MOHIT
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