Compete the shortest distance between the circle x^2+y^2-10x-14y-151=0 and the point (-7,2) .

Question

Sourabh Singh · Answer

Hii You have to find the equation of normal passing from the given point . Find out the length from the point given and the centre of circle, you can get the answer

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Compete the shortest distance between the circle x^2+y^2-10x-14y-151=0 and the point (-7,2) .

Compete the shortest distance between the circle x^2+y^2-10x-14y-151=0 and the point (-7,2) .

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Compete the shortest distance between the circle x^2+y^2-10x-14y-151=0 and the point (-7,2) .

Compete the shortest distance between the circle x^2+y^2-10x-14y-151=0 and the point (-7,2) .

1 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Analytical Geometry

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

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