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`        let algebraic sum of perpendicular distances from points (2,0) (0,2) (1,1) to a variable straight line be zero then line passes through a fixed point whose coordinates are`
7 years ago

28 Points
```										Dear Shubhankar Sinha,
Ans:- Let the eq of the line be ax+by+c=0
it's distances from the three points are
D1=(2a+0b+c)/K..................(1)
D2=((0a+2b+c)/K...................(2)
D3=(a+b+c)/K.......................(3)
Where K=√(a²+b²)
Adding 1, 2, 3 we get
D1+D2+D3=(3a+3b+3c)/K
=3(a+b+c)/K
As the sum is 0 hence a+b+c=0
So, the line passes through theFixed point (1,1)         [ ax+by+c=0  putting (1,1) point in x,y we get a1+b1+c=a+b+c=0]

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.
All the best Shubhankar Sinha !!!

Regards,
```
7 years ago
Aisha D'souza
26 Points
```										let the algebraic sum of the perpendicular distance from (3,0),(0,3) and (2,2) to a variable line is zero, then the line passes through a fixed point whose co-ordinates are?
```
2 years ago
SANDEEP
13 Points
```										Let the variable line be px+qy+1=0 then given condition P1+P2+P3=3p+3q+3=0Or p+q+1=0Condition of upper eq show that the variable line passes through the point (1,1)
```
3 months ago
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