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deepikA thotlavalluri Grade: 11
        

A square is inscribed in the circle x2 +y2 -10x-6y+30=0.One side of the square is parallel to the liney=x+3,then one vertex of the square is

7 years ago

Answers : (1)

Nehal Wani
21 Points
										

radius of circle = 2 = half of diagonal of square


therefore perpendicular distance of center of circle(5,3) from side of square=√2


equation of one side of square : y=x+k


by distance formula,


|5+k-3|/√2=√2


k=0,-4


the two side of square are: y=x and y=x-4


solving the lines with the equation of circle, we get:


vertices: (3,3),(5,5),(5,1),(7,3)

7 years ago
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