MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
samridhi sinha Grade: 11
        Find the equation to the tangent to the circle x(squared)+y(squared)=5 which is perpendicular to the line 4x-2y+3=0.
7 years ago

Answers : (1)

Ramesh V
70 Points
										

slope of given line is 2, eqn is y = 2x + 3/2


its perpendicular eqn is of form , y = -1/2x + c where is c in intercept to be found ,as


this eqn is tangent , its perpendicular distance from center is equal to radius of 5 units


5 = c / (5/4)1/2


so , c = 5/2*(5)1/2


so eqn of tangent is : 2y + x - 5*(5)1/2 =0


--


regards


Ramesh

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 3,180 off
USE CODE: CART20
Get extra Rs. 297 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details