Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 350 off

				   Find the equation to the tangent to the circle x(squared)+y(squared)=5 which is perpendicular to the line 4x-2y+3=0.

6 years ago


Answers : (1)


slope of given line is 2, eqn is y = 2x + 3/2

its perpendicular eqn is of form , y = -1/2x + c where is c in intercept to be found ,as

this eqn is tangent , its perpendicular distance from center is equal to radius of 5 units

5 = c / (5/4)1/2

so , c = 5/2*(5)1/2

so eqn of tangent is : 2y + x - 5*(5)1/2 =0




6 years ago

Post Your Answer

Other Related Questions on Analytical Geometry

If a+b+c=0,then the family of lines 3ax + by + 2c = 0 pass through the fixed point
Dividing the whole eqn. by 2 and comparing with a+b+c = 0 3ax + by + 2c = 0 we get, 3a/2 x + b/2 y + c = 0 3x/2 = 1 x = 2/3 and y/2 = 1 y = 2. hence (x,y) that is (2/3 , 2) is the fixed...
2017 years ago
find the locus of the middle points of chord of circle x^2+y^2=a^2 which pass through fixed point (h,k)
Let (x 1 , y 1 ) be the middle point of chord of circle x 2 +y 2 =a 2 Then equation of chord can be written as xx 1 +yy 1 =x 1 2 +y 1 2 Since chord passes through (h,k) we have hx 1 +ky 1...
Ajay 2 months ago
circle passing through origin and center lying on the x-axis is x^2+y^2......M is mid point of the AB.
kumar 2 months ago
if the coordinate of variable P be (cos@ sin@,sin@-cos@) where @ is the parameter, then the locus of point P is
take h =cos@ sin@ and k =sin@-cos@ now u have to eliminate @ from both the eqns that’s it Thanks
Nishant Vora 2 months ago
let a,b,c be the sides oppositwe the angles A,B,C of triangle ABC.find the value of k a+b=ck
refer R.D. sharma Book there you will find all the answers of your queries. its the best book for all the geometric questions
aadish jain one month ago
tanx/x plllllllllz
what is your question
maneeshbabu one year ago
If sin theta + cos theta =p and sec thet + cosec theta = q , show that q ( p square - 1) = 2p
q(p^2-1)= sec theta + cosec theta((sin theta +cos theta)^2 -1) sec theta + cosec theta( sin^2 theta + cos^2 theta + 2 sin theta cos theta)-1) (sin^2 theta + cos^2 theta=1) 1/cos theta +1...
Jayanth Miriyala 2 months ago
q(p square -1)=sec theta +cosec theta ( (sin theta +cos theta )square -1)=1/cos theta +1/sin theta (2sin theta cos theta )=(sin theta +cos theta )2=2p
SYED FAHIM AHAMAD 2 months ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,750 off

Get extra R 350 off

More Questions On Analytical Geometry

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details