MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
pallavi pradeep bhardwaj Grade:
        

If the circles x2+y2+2x+2ky+6=0 and x2+y2+2ky+k=0 intersect orthogonally, then k is :

(A) 2 or –3/2                                    (B) –2 or 3/2
(C) 2 or 3/2                                       (D) (2,+∞)

7 years ago

Answers : (1)

Ramesh V
70 Points
										

4143-285_5850_img1.png


R2 + r2 = distance between centers is condition of orthogonality


the circles are : (x+1)2+(y+k)2 = k2-5


                       x2 + (y+k)2 = k2-k


its : k2-5+k2-k =  1


      which gives k = 2 , -3/2


option A


--


Please feel free to post as many doubts on our disucssion forum as you can. If you find any question difficult
to understand - post it here and we will get you the answer and detailed solution very quickly.We are all
IITians and here to help you in your IIT JEE preparation. All the best.

Regards,
Ramesh  
IIT Kgp - 05 batch



7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,000 off
USE CODE: MOB20
Get extra R 280 off
USE CODE: MOB20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details