write natural numbers 1 to 2015 one after another in ascending order to obtain a long number N=123456789101112........2013201420142015. the remainder of this number when divided by 9 is x. find x.

Question

Saurabh Koranglekar · Answer

Dear student

A number isdivisibleby9if the sum of the digits isdivisibleby9

Please use this property to club such numbers from the string so that their sum is 9 and

finally, you will end with a digit from the set { 0,1,2,3,4,5,6,7,8} as the remaining of the string

then the remainder would be that remainder

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write natural numbers 1 to 2015 one after another in ascending order to obtain a long number N=123456789101112........2013201420142015. the remainder of this number when divided by 9 is x. find x.

write natural numbers 1 to 2015 one after another in ascending order to obtain a long number N=123456789101112........2013201420142015. the remainder of this number when divided by 9 is x. find x.

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write natural numbers 1 to 2015 one after another in ascending order to obtain a long number N=123456789101112........2013201420142015. the remainder of this number when divided by 9 is x. find x.

write natural numbers 1 to 2015 one after another in ascending order to obtain a long number N=123456789101112........2013201420142015. the remainder of this number when divided by 9 is x. find x.

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