0

Guest

Courses New

the number of possible outcomes in a throw of n ordinary dice in which atlleast one of the dice shows an odd number is

the number of possible outcomes in a throw of n ordinary dice in which atlleast one of the dice shows an odd number is

Grade:12th Pass

2 Answers

Harsh Patodia IIT Roorkee
askIITians Faculty 907 Points
7 years ago
One dice out of n will have output 1,3,5 so three choices other dices will have 6 choices
So total will be 3.6.6.6.6.6.6. . . =3 x6n-1
demesaikiran
37 Points
7 years ago
IT IS NOTHING BUT TOTAL NUMBER OF WAYS IN WHICH ALL THE NUMBERS WILL COME -NO DICE SHOWS AN ODD NUMBER(1,3,5)
SO TOTAL NUMBER OF EVEN NUMBERS ARE (2,4,6) HAS POSSIBILITIES TO OCCUR IS 3.3.3.3.3.3.3........N TIMES 
HERE TOTAL NUMBER OF WAYS IN WHICH ALL NUMBERS WILL COME IS =6.6.6.6.6.6.6.........n TIMES 
THERE FORE,REQUIRED ANSWER IS 6^n-3^n.

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More