if a,b,c,d are natural numbers,and a=bc,b=cd,c=da and d=ab then (a+b)(b+c)(c+d)(d+a)=

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Rakesh mehta · Answer

got it. multiplying all;abcd=1 a/b=bc/cd a/b=b/d d=ab a*ab=b^2 a^2=b By substituting equation , d=a^3 c=a^4 b=a^2 a=a multiplying these all abcd=a^10 as we have earlier abcd=1 1=a^10 a=1 b=1 c=1 d=1 solution= 16

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if a,b,c,d are natural numbers,and a=bc,b=cd,c=da and d=ab then (a+b)(b+c)(c+d)(d+a)=

if a,b,c,d are natural numbers,and a=bc,b=cd,c=da and d=ab then (a+b)(b+c)(c+d)(d+a)=

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if a,b,c,d are natural numbers,and a=bc,b=cd,c=da and d=ab then (a+b)(b+c)(c+d)(d+a)=

if a,b,c,d are natural numbers,and a=bc,b=cd,c=da and d=ab then (a+b)(b+c)(c+d)(d+a)=

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