MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Tapasranjan Das Grade: 12
        

Q:Square root of two succesive natural numbers greater than N2 differ by β ,then β is less than


A. 1/2N


B.1/N


C.2/N


D.4/N

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Tapasranjan Das


let numbers are x and x+1


√(x+1) -√x =β .............1


square


(x+1) +x -2√x√(x+1)  = β2


2x + (1-β2) = 2√x√(x+1)


square again


4x2 +(1-β2)2 + 4x(1-β2) = 4x(x+1)


(1-β2)2 - 4xβ2 = 0


  x = (1-β2)2 / 4β2


 given  x  >N2


so


(1-β2)2 / 4β>N2


(1-β2) / β  >2N


 1/β  -β  > 2N


from equation 1


 β >0


so 1/β > 2N


 β <1/2N




Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and

detailed
solution very  quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin







7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details