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`        Find real part of z=tan(a+ib)`
7 years ago

147 Points
```										Dear ashish
z=tan(a+ib)
let z = x+iy
so
x+iy = tan(a+ib)
x-iy = tan (a-ib)
2x = tan(a+ib)  + tan  (a-ib)
=sin ( a+ib+a -ib)/2cos(a+ib)cos(a-ib)
= sin2a / (cos2a + cos2ib)
= sin2a/(cos2a + cosh2b)
x =  sin2a/2(cos2a + cosh2b)

in above derivation we use cosi2b = cosh2b
this a formula  and cosh2b is a real value,not imaginarry
coshx =(ex + e-x )/2
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very  quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
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