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An n- bit string is n- digit "word" , each digit of which is either 0 or 1.

Find the no. of n- bit strings containing both the digit zero and one.

6 years ago


Answers : (1)


Dear Sanchit

Each position of n digit string can be filled by 2 ways either 0 or 1

so total number os such word is 

     =2*2*2*2*2 .......n times


 but it include that case also which has 0 at all position and 1 at all position

So total number of desired way =2n-2

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6 years ago

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