At a certain stage of a criminal investigation, the inspector in-charge is 60% convince of the guilt of a certain suspect. Suppose now a piece of evidence that shows the criminal has brown hair is uncovered. If the inspector in-charge is convinced that the suspect is not guilty then there is 20% chance that he/she has brown hair. What is the probability that the inspector in-charge is convinced that the suspect is guilty given he/she has brown hair?

2 years ago

Share

Answers : (1)

                                        

Hello student,



•G: event that the suspect is guilty


•C: event that he possesses the characteristic of the criminal


•P(G|C) is ?


•P(G|C) = P(GC)/P(C)


= P(C|G)P(G) / [P(C|G)P(G) + P(C|Gc)P(Gc)]


= 1(.6)/[1(.6) + (.15)(.4)] ≈ .91



Thanks and Regards


Shaik Aasif


askIITians faculty

7 months ago

Post Your Answer

More Questions On Algebra

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
Find all real values of m for which the inequalty mx 2 - 4x + 3m + 1 >0 is satisfied for all positive x.
 
 
Hello Student, Please find the solution The value of this quadratic is always positive (>0) So graph will always be above x-axis therefore the condition will be :- D>0 and a>0...
  img
Nishant Vora 4 months ago
m=2-(3)^(1/2) Find the value of (m^6+m^5+m^4+1)/m^3
 
 
Hello student, This may help you m = 2 – 3^(1/2), and rationalising this we get m + 1/m = 4. som^2 = 4m-1 Given equation is= (m^3+1/m^3) +m^2+m From the identity if a+b+c = 0 gives...
  img
SHAIK AASIF AHAMED 6 months ago
 
Hello student, Please find the answer to your question below as m= m 2 =7- m 3 =26-15 1/m 3 =26+15 Given (m 6 +m 5 +m 4 +1)/m 3 =m+m 2+ m 3 +1/m 3 =2- +7-4 +26-15 +26+15 =61-5
  img
SHAIK AASIF AHAMED 6 months ago
 
m = 2 – 3^(1/2), and so m + 1/m = 4. We can also write this last equation as m^2 = 4m-1 Given expression = (m^3+1/m^3) +m^2+m Now, using the identity: a+b+c = 0 implies a^3+b^3+c^3 = 3abc,...
 
mycroft holmes 6 months ago
if [sqrt(a) + sqrt(b)]/ [sqrt(a) – sqrt(b)] + [sqrt(a) – sqrt(b)]/ [sqrt(a) + sqrt(b)] = a – b, then prove that a – b = sqrt (2)
 
 
Hello student, Please find the answer to your question below Given Taking lcm we get On expanding we get (a-b) 2 =2(a+b) so you get (a-b)= I think there is some error in the question
  img
SHAIK AASIF AHAMED 4 months ago
If the distance between circumcentre and orthocentre of triangle whose vertices are (1,5) (2,3) (4,4) is k/√10 then sum of abscissa of points which are k distance away from the point (3,2)...
 
 
A (1,5) B (2,3) C (4,4) AB= √5 units BC=√5 units AC= √10 units Hence given triangle is right angled triangle ( AB2 + BC2 = AC2) at B Orthocenter is B only CIrcumcenter for...
  img
Harsh Patodia 4 months ago
1) sin65 + sin43 – sin29 - sin7=? Angles are in degrees. ​2) sin(pi cot theta)= cos(pi tan theta) then cot2theta=? 3)cosxcosysin(x-y) + cosycoszsin(y-z) + coszcosxsin(z-x) +...
 
 
2 Solve for tan(theta) and find the value of tan2(theta). Reciprocate to get to the value of cot2(theta) Requested to post only one question per post.
  img
Ravi 2 months ago
circles of radii 5,5,8 touch each other externally. Find the radius of the circle which touches all the three circles internally.
 
 
?
  img
Pushkar Aditya 21 days ago
 
if you draw yhe diagram, and put C1,C2 the centre of circle with r=5. c3 the centre of circle of r=3. Since circle(c3) touch the both circle C 3 C 1 =C 3 C 1 -->C3 lies on perp. bisector of...
 
Abhishek Singh 19 days ago
 
@ abhishek singh ..that is the easy one . it is for externally that u r telling .. the question reads internally my frnd.
 
sarim khan 21 days ago
View all Questions »