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                   xn xn+2 xn+3

yn yn+2 yn+3
zn zn+2 zn+3

3 years ago

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Latika Leekha
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one year ago

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Now pls explain the answer....
 
 
55 PLZ APPROVE IF correct and want solution
 
Nicho priyatham 16 days ago
 
i got -55
 
noogler 11 days ago
 
55
 
Aakash 11 days ago
Find the real values of the parameter ‘a’ for which atleast one complex number z =x+iy satisfies both the equality |z-ai|=a+4 and the inequality |z-2| is less than 1 .
 
 
Ans: Hello Student, Please find the answer to your question below For having atleast one solution for both the equation, the first circle should intersect with 2 nd circle on the x –...
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Jitender Singh 11 months ago
 
first of all is not right as given in qus this is less than 1 not equal second thing this qus is from resonannce assignment and ans is (-21/10 ,- 5/6)
 
saurabh 11 months ago
If ((x-1)(x-2) 2 (x-3) 3 )/((x-4) 2 (x-5) 6 ) > 0, then find the values of x.
 
 
the answer is (−infinity,1) U (3,infinity)
 
Shubham Singh 2 months ago
 
6
 
SIDHARTH JAIN 2 months ago
 
N should be higher than D upto 3 N will 0 and and 4 &5 Dwill be 0 so the first number after that is 6 which nmake sense .
 
SIDHARTH JAIN 2 months ago
If u=f(x) and v=g(x) then d(uv)/dx is
 
 
its quite simple , rather its product rule for differentiation anyway uv=f(x).g(x) d(uv)/dx = f(x) g , (x) + g(x) f , (x) it is answer APPROVE IF USEFUL
 
ng29 one month ago
 
its very simple first take gx constant and diffrentiade and similarly take fs constant and diffrentiate gx
 
grenade one month ago
 
hey are you solving integration by parts but all the way answer is d(uv)/dx = f(x) g , (x) + g(x) f , (x)
 
Gman Namg one month ago
if the extremities of a diagonal of a square are (1,-2,3) and (2,-3,5) then the lenght of its side is ?
 
 
Length of the diagonal of square is √ ((1-2) 2 + (-2+3) 2 +(3-5) 2 ) = √6 We aslo know that length of square is √2 times the side. This implies √2a= √6 ( where...
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Harsh Patodia 9 months ago
what is the antiderivative of sinx
 
 
anti derivative means integration and its value equals theta1 theta2 ∫sinx.dx = -cos(theta1-theta2) +c approve if useful
 
grenade one month ago
 
-COSX
 
noogler one month ago
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