Total Price: R

There are no items in this cart.
Continue Shopping

let A= set of 3x3 determinat having entries +1 or -1, if a determinat A1 is chosen randomly from the set of A,then the probability that the product of the elements of any row or any column of A1 is -1 is _

3 years ago


Answers : (2)


I am not sure, but here is my best guess.



Sample Space = 2^9


(There are 9 positions, each position has two possiblities (-1 or +1) )


Favourable Outcomes :


Number of -1 in each row or coloumn should be odd.

So we get two cases here.

(i) No. of -1 in each row and coloumn is 3

(ii) No. of -1 in each row and coloumn is 1


Case 1:


This case can occur only when all the elements in the matrix is -1.


No. of favourable cases = 1


Case 2:


Consider the matrix row wise.

In the first row, you can put the -1 in any of the 3 places.

In the second row, you can put the -1 in two places (no below the previous one)

In the third row, you can put the -1 in only one place (remaining one, not below the other two).


So you get 3*2*1 = 6 possibilities in this case.


Total no. of favourable outcome = 6+1 = 7


So required probability is 7/29 ..

3 years ago

Okay I missed a case.


All digits in a single row are -1. Rest of the elements are 1.

So we get 3 more cases.


So Probability = 10/2^9

3 years ago

Post Your Answer

More Questions On Algebra

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details
the 3 rd term and 7 th term of an A.P are 13 & 33 respy..find the nth term of the ap
Given, 3 rd term is 13.So, a+2d=13 7 th term is 33.So,a+6d=33 On solving, a=3,d=5 T n =a+(n-1)d T n =3+5n-5=5n-2 So, the nth term of this A.P is 5n-2.
CHANDRA KIRAN 3 months ago
Given, 3 rd term is 13.So, a+2d=13 7 th term is 33.So,a+6d=33 On solving, a=3,d=5 T n =a+(n-1)d T n =3+5n-5=5n-2 So, the nth term of this A.P is 5n-2.
CHANDRA KIRAN 3 months ago
a+2d=13 and a+6d=33. On solving, a=3,d=5. T n =a+(n-1)d=5n-2.
viswanath 3 months ago
Find the greatest term in the expansion of (7-5x)^2 where x=2/3 Please explain the steps. Thankyou in advance.
Hello Student. Please find the solution (7-5x)^2 = 49 + 25x^2 – 70x so first term = 49 second term = -70*2/3 third term = 25 x^2 = 25*4/9 = 11.11 So 49 is greatest...
Nishant Vora 8 months ago
Sorry sir.. i am extremely sorry.. Actually i typed in the wrong question.. it was (7-5x)^11, where x=2/3.. I am extremely sorry once again. Sir please give me the correct answer for this.
Swagat Bordoloi 8 months ago
the position o the vectors A,B,C of a triangle are i-j-3k, 2i+j-2k and -5i+2j-6k respectively.the length of the bisector AD of the angle BAC where D is on the line segment BC,is 1-15/2 2-¼...
if this is not the answer then please post the solution .. but think this is a correct approach
abhishek singh 8 months ago
see as AD is internal bisector o angle BAC , it ( that is the point D ) will divide BD and DC in the ratio of AB/AC i.e 1:3 . now using the division formula get the cordinate of D . and...
abhishek singh 8 months ago
to find the equation of tangent to any curve from point (x1,y1) just replace y^2 by yy1; x^2 by xx1; y by (y+y1)/2 ;x by (x+x1)/2 and constant term is remain unchanged, so in your question...
PRATYUSH MISHRA 10 months ago
thanks buddy!!
Bharat Makkar 10 months ago
m,n are integer with 0
Please elaborate the question. ............................................................................................................................................................
Ravi 5 months ago
The complex no. sinx + i cos2x cosx-i sin2x are conjugate to each other if
Hello Student, Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty
Arun Kumar one year ago
View all Questions »