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Solve For x :


 


x^3 - 3x = sqrt(x+2)

4 years ago

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Answers : (1)

										

sq. both the sides.. then taking x^2 common..


solving


x=-1 or x=2..


 


 


approve if u like

4 years ago

Post Your Answer

p+q=4,p=0.q=?
 
 
4
 
OUTPASS 8 months ago
 
4
 
charan 8 months ago
 
4
 
RAJU 8 months ago
if a 2, b 2, c 2 are in A.P. then prove that.. a/b+c, b/c+a, c/a+b
 
 
If a 2 , b 2 , c 2 are in A.P., so are a 2 +ab+bc+ca, b 2 +ab+bc+ca, and c 2 +ab+bc+ca i.e. (a+b)(c+a), (b+c)(a+b), (c+a)(b+c) are in A.P. Multiplying the three terms by (a+b+c)/...
 
mycroft holmes 8 months ago
 
If a 2 , b 2 , c 2 are in A.P., so are a 2 +ab+bc+ca, b 2 +ab+bc+ca, and c 2 +ab+bc+ca i.e. (a+b)(c+a), (b+c)(a+b), (c+a)(b+c) are in A.P. Multiplying the three terms by (a+b+c)/...
 
mycroft holmes 8 months ago
 
it is very easy use b 2 -a 2 =c 2 -b 2
 
dinesh 8 months ago
How to find rank of the word examination in dictionary
 
 
plsss mention the word...one can explain the permutation combination behind it thru’ an example.
 
saayan mitra 8 months ago
 
plsss mention the word...one can explain the permutation combination behind it thru’ an example.
 
saayan mitra 8 months ago
 
plsss mention the word...one can explain the permutation combination behind it thru’ an example.
 
saayan mitra 8 months ago
tan75
 
 
TAN 75 =TAN ( 45 + 30 ) =(TAN 45 + TAN 30 ) / ( 1-TAN 45 TAN 30 ) =(1+1÷√3)÷(1−(1×1÷√3)) =3.732050808 ANSWER IS TAN75 = 3.732050808. IF YOU LIKE THIS ANSWER PLZ APPROVE IT.
 
SAI SARDAR 8 months ago
 
PLZ APPROVE
 
Nikhil Upadhyay 8 months ago
 
PLZ APPROVE
 
Nikhil Upadhyay 8 months ago
Can anyone solve this problem and provide the solution
 
 
as x tends to infinty x= x-1 =x+1 f(x)= 1/2( f(x)+ 3/f(x)) f(x)/2 = 3/2f(x) f(x) 2 = 3 Hence b
  img
Harsh Patodia one month ago
 
the answer for your question is square root of three.that will come by solving all the best for your bright future
 
Prabhakar ch one month ago
is arihant differential and inegral calculus by amit agrwal is good book for iit and board exam
 
 
Yes it is a good book indeed but it is of advanced type so it may not be use for board exam.
 
VINEETH N 9 months ago
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