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In how many ways can a lawn tennis mixed doubles be made up from seven married couples if no husband and wife play in the same set?

7 years ago

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Answers : (5)

										

SELECT 2 PERSONS FROM 14


NO. OF WAYS = 14C2=91


IN THISTHERE ARE 7 WAYS IN WHICH HUSBAND WIFE COME TOGETHER


TOTAL WAYS= 91-7=84


OUT OF THESE 84 TEAMS WE HAVE TO SELECT 2 TEAMS


NO. OF WAYS = 84C2 = 3486 WAYS ANS

7 years ago
										

Thanks for replying. But the answer is 840 only. I think u misjudged the question. in first step u took 14C2 , in this case it is possible that we select 2 husbands but no wife... instead of this it must be like this


7C2 x 7C2 since we want two husbands but two wives also. these are 21 x 21 = 441 ways.


now we want to deduct the unfavorable cases i.e 14 cases  i m stuck up at this point how to get the answer ahead? 


can anyone help?


 


actually this question is given in permutation chapter can this be solved without combination ?

7 years ago
										

it should be 210.


as u select two husbands u will have five wives left to select from.......

7 years ago
										

a regular polygon of 9 sides each of length 2 unit is inscribed in a circle the radius of circle is

5 years ago
										Ans= 840 Since in a mixed doubles 2 player play in the que. One husband and one wife will play. No. Of ways husband`s can be chosed is 7p2 and no. Of ways wife could be chosen will be 5p2 as the wife of two husband chosen shouldn`t include.                        thus and 7p2 × 5p2= 840
										
4 months ago

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