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` `In how many ways can a lawn tennis mixed doubles be made up from seven married couples if no husband and wife play in the same set?

7 years ago

SELECT 2 PERSONS FROM 14

NO. OF WAYS = 14C2=91

IN THISTHERE ARE 7 WAYS IN WHICH HUSBAND WIFE COME TOGETHER

TOTAL WAYS= 91-7=84

OUT OF THESE 84 TEAMS WE HAVE TO SELECT 2 TEAMS

NO. OF WAYS = 84C2 = 3486 WAYS ANS

7 years ago

Thanks for replying. But the answer is 840 only. I think u misjudged the question. in first step u took 14C2 , in this case it is possible that we select 2 husbands but no wife... instead of this it must be like this

7C2 x 7C2 since we want two husbands but two wives also. these are 21 x 21 = 441 ways.

now we want to deduct the unfavorable cases i.e 14 cases i m stuck up at this point how to get the answer ahead?

can anyone help?

actually this question is given in permutation chapter can this be solved without combination ?

7 years ago

it should be 210.

as u select two husbands u will have five wives left to select from.......

7 years ago

a regular polygon of 9 sides each of length 2 unit is inscribed in a circle the radius of circle is

5 years ago

Ans= 840 Since in a mixed doubles 2 player play in the que. One husband and one wife will play. No. Of ways husband`s can be chosed is 7p2 and no. Of ways wife could be chosen will be 5p2 as the wife of two husband chosen shouldn`t include. thus and 7p2 × 5p2= 840

8 months ago

In any of the matches, the total players playing in the game would be 4 i.e (one male one female) vs (one male one female). Also the male and female constituting the team should not be married couples. So for a match, 2 males and 2 females are essential. Therefore we select 2 males from total 7 males by 7P2. Now, females to be selected shouldn't be the wives of the 2 males selected. Therefore we select 2 females fromfemales (The two females excluded are the wives of the selected males). So we use 5P2 for females.5Thus total no. of arrangements of all possible matches becomes 5P2 * 7P2.

2 months ago

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