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yudhisther sharma sharma Grade: 12
        

In how many ways can a lawn tennis mixed doubles be made up from seven married couples if no husband and wife play in the same set?

7 years ago

Answers : (6)

ARCHIT SINGHAL
18 Points
										

SELECT 2 PERSONS FROM 14


NO. OF WAYS = 14C2=91


IN THISTHERE ARE 7 WAYS IN WHICH HUSBAND WIFE COME TOGETHER


TOTAL WAYS= 91-7=84


OUT OF THESE 84 TEAMS WE HAVE TO SELECT 2 TEAMS


NO. OF WAYS = 84C2 = 3486 WAYS ANS

7 years ago
yudhisther sharma sharma
18 Points
										

Thanks for replying. But the answer is 840 only. I think u misjudged the question. in first step u took 14C2 , in this case it is possible that we select 2 husbands but no wife... instead of this it must be like this


7C2 x 7C2 since we want two husbands but two wives also. these are 21 x 21 = 441 ways.


now we want to deduct the unfavorable cases i.e 14 cases  i m stuck up at this point how to get the answer ahead? 


can anyone help?


 


actually this question is given in permutation chapter can this be solved without combination ?

7 years ago
nishant kumar agarwal
20 Points
										

it should be 210.


as u select two husbands u will have five wives left to select from.......

7 years ago
praman gupta
16 Points
										

a regular polygon of 9 sides each of length 2 unit is inscribed in a circle the radius of circle is

5 years ago
Raj Dhakad
11 Points
										Ans= 840 Since in a mixed doubles 2 player play in the que. One husband and one wife will play. No. Of ways husband`s can be chosed is 7p2 and no. Of ways wife could be chosen will be 5p2 as the wife of two husband chosen shouldn`t include.                        thus and 7p2 × 5p2= 840
										
10 months ago
Prateek Garg
26 Points
										
In any of the matches, the total players playing in the game would be 4 i.e (one male one female) vs (one male one female). Also the male and female constituting the team should not be married couples. So for a match, 2 males and 2 females are essential. Therefore we select 2 males from total 7 males by 7P2. Now, females to be selected shouldn't be the wives of the 2 males selected. Therefore we select 2 females from females (The two females excluded are the wives of the selected males). So we use 5P2 for females.
Thus total no. of arrangements of all possible matches becomes 5P2 * 7P2.
4 months ago
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