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Tushar Watts Grade: 12
        

The number of all possible triplets (a1, a2,a3) such that a1 + a2 cos2x +a3 sin 2 x = 0 for all x is


(a) 0     (b) 1   (c)3    (d) infinity


 

7 years ago

Answers : (1)

Ramesh V
70 Points
										

A + B(1-t2) + Ct2      where t2 = sin2x   , i.e., 0 =< t2 =< 1 as -1<sin x<1


t2 = (2B-C)/(A+B)


0 =< (2B-C)/(A+B) =< 1


i.e., 2B >= C  and A+C>=B


the possible triplets for which the above inequalities satisfy are :


(A,B,C) in order of (0,1,1) (1,1,0) (0,0,0) (2,3,1) and so on


answer is infinity


--


regards


Ramesh



7 years ago
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