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```        solve for x:
log1/3(x-1) + log1/3(x+1) + log√3(5-x) < 1
plz helpppp.....```
6 years ago

## Answers : (1)

510 Points
```										logax = logx/loga                 (property)
logxb = blogx                       (property)

log1/3(x-1) + log1/3(x+1) + log (5-x) < 1

logx-1/log1/3  + logx+1/log1/3 + log5-x/log√3 <1

-logx-1/log3  - logx+1/log3 + 2log5-x/log3 <1
-logx-1 - logx+1 + 2log5-x < log3                       (logab = loga + logb)
2log5-x - logx2-1 < log3
2log5-x < log3 + logx2-1
2log5-x < log3(x2-1)
(5-x)2 < 3(x2-1)
now solve this & get the ans

```
6 years ago
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