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paradox xyz cool Grade: 11
        

solve for x:


log1/3(x-1) + log1/3(x+1) + log√3(5-x) < 1


plz helpppp.....

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

logax = logx/loga                 (property)


logxb = blogx                       (property)



log1/3(x-1) + log1/3(x+1) + log (5-x) < 1




logx-1/log1/3  + logx+1/log1/3 + log5-x/log√3 <1


 


-logx-1/log3  - logx+1/log3 + 2log5-x/log3 <1


-logx-1 - logx+1 + 2log5-x < log3                       (logab = loga + logb)


 2log5-x - logx2-1 < log3


 2log5-x < log3 + logx2-1


 2log5-x < log3(x2-1)


   (5-x)2 < 3(x2-1)


   now solve this & get the ans


 


6 years ago
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