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MANOJ KUMAR Grade: 12
        

lower limit k=1 upper limit 10 (sin2kpi/11+icos2kpi/11)

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

Z = sin2kpi/11 + icos2kpi/11


Z = Aei@                    (ellulers form)


A = (sin2@+cos2@)1/2 = 1 ,


@ = 2kpi/11


Z = ei(2kpi/11) 


sigma Z  = sigma ei(2kpi/11)   lim k=1 to k=10


            =ei[2pi/11 (1+2+3........10)]  (AP series)                         [ sum of Ap is n/2(2a+(n-1)d]


           =ei[2pi/11(55)]


           =ei10pi = cos10pi + isin10pi = 1

6 years ago
mycroft holmes
266 Points
										

6 years ago
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