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`        What does the equation (a-b)(x^2+Y^2)-2abx = 0 becomes if the origin is shifted to the point (ab/a-b, 0) without rotation?`
6 years ago

Aniket Patra
48 Points
```										Dear Chanchal,
Apply the concept of 'Parallal Transformation of Coordinate Axes'..As the origin has been shifted to (ab/a-b,0),so we can right x=ab/a-b+ab/a-b where the second ab/a-b=h{the distance of the new cordinate from the old one,here distance between (0,0) and (ab/a-b)}.Now put the value of x and solve..Most probably the equation would come out to be a line parallel to x-axis.

Goodluck and Warm Wishes,
```
6 years ago
510 Points
```										initial coordinates of origin = (0,0)  &  the coordinates of general point = (X,Y)
final coordinates of origin = (ab/a-b,0) , & the coordinates of general point =(X1,Y1)
from here we can say
X1 = X+ab/a-b     &  Y1 = Y+0=Y
so keeping Y coordinate unchanged replace X by X+ab/a-b u will get the required equation....
```
6 years ago
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