Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        In an exam 70% passed in English 65% passed in Maths while 27% failed in both.If 248 candidates  passed in both.Find the total number of candidates`
7 years ago

30 Points
```										Dear Vivek,Solution:-Let the total no. of candidates are 'n'.
Then, no. of candidates passed in English (E) = 0.7n,
no. of candidates passed in Maths (M) = 0.65n, and
no. of candidates neither passed in English nor in Maths (E‾ ∩ M‾) = 0.27n.
[Here, E‾ and  M‾ are the complements of E and M respectively.]
no. of candidates passed in both (E ∩ M) = 248
We know, (E U M) = n - (E‾ ∩ M‾) [Very standard formula]
and (E U M) = (E) + (M) - (E ∩ M) [Another standard formula]
These two formulas will give-
n - (E‾ ∩  M‾) = (E) + (M) - (E ∩ M)
n - 0.27n = 0.7n+0.65n - 248
n = 400 (Ans)
Please feel free to post as many doubts on our discussion forum as you can. If you find any questionDifficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best Vivek!!!Regards,Askiitians ExpertsPriyansh Bajaj
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details