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```

sir
if x^3-31x+30=0
then how we will find values of x

```
7 years ago

30 Points
```
Dear Sunil Sahu,
Solution:- General approach for solving the cubic equation is to first find one root (say 'a') by Hit and Trial method. Then, you will break the equation into two parts like  (x-a)(x^2 - bx + c) = 0.
After this step, you know the one root and you get one quadratic equation (in above case, it is x^2 - bx + c = 0). Solve the quadratic equation and get another two roots.
For example (applying this method to your problem),
(1) x^3 - 31x +30 = 0
Putting x=1 in the equation.
1 - 31 +30 = 0 which is true, which implies x = 1 is one of the root.
In most of the cases, putting 1,2,0,-1,-2,1/2 or -1/2 works.
(2) x^3 - 31x +30 = 0 can also be written as (x-1)(x^2 + x - 30) = 0
(3) Now solve the equation- x^2 + x - 30 =  0
It gives x = 5 and -6
Ans- x=1, 5 and -6
Please feel free to post as many doubts on our discussion forum as  you can. If you find any question Difficult to understand - post it  here and we will get you the answer and detailed solution very quickly.  We are all IITians and here to help you in your IIT JEE preparation.
All the best Sunil Sahu!!!

Regards,
Priyansh Bajaj

```
7 years ago
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