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Aniket Patra Grade: Upto college level
`        z^n = K (K is real).The sum of the arguments of all the roots of this equation is an odd multiple of pi..When is this possible? That is the relation between n and k.`
7 years ago

21 Points
```										Dear Aniket,
The sum of all the roots of zn=K is an odd multiple of π when K is negative.
Roots of this equation for K<0 will be z=|K|1/nei(2m+1)π/n where m=0,1,2,...,n-1. Clearly the sum of roots is an odd multiple of π.
e.g. z3=-1
=> z=eiπ/3,eiπ,ei5π/3
Sum of arguments = 3π
Hope this helps.
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```
7 years ago
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