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there are three bags first containig 1 white 2 red 3 green ,second 2 white 3 red 1 green balls and third 3 white 1 red 2 green balls. two balls drawn from a bag chosen at random. these are found to be one red and one white.find the probability that the balls so drawn came from second bag.
answer:(2/6)(3/6)/((2/6)(3/6)+(1/6)(3/6)+(1/6)(2/6)) =6/(6+2+3)=6/11
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