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  The greatest term of the expansion (2x + 5y)13 where x = 10, y = 2 is
 
 
 
 
 
 
 
  None

 


 











 






























  The binomial expansion of n N contain a term independent of x :
 
   only if k is an integers
 
  only if k is a natural numbers.
 
  only if k is rational
 
  for any real k.

 


 











 






























  The coefficient of x50 in (1 + x)41 (1 - x + x2)40 is
 
  1
 
  2
 
  3
 
  0

 


 




























Given that the term of the expansion (x1/3 - x-1/2)15 which does not contain x is 5 m where m N , then m =
1100
1010
1001
none










0 out of 4 marks (content provider)

Correct Answer: 3
Solution:
Ans: 3





























Q. 8 In the binomial (21/3 + 3-1/3)n, if the ratio of the seventh term from the beginning of the expansion to the seventh term from its end is 1/6 , then n =
6
9
12
15










0 out of 4 marks (content provider)

Correct Answer: 2
Solution:
Ans: 2





























Q. 9 The coefficient of x49 in the expansion of (x - 1) ..... is equal to
- 2
+ ve coefficient of x
- ve coefficient of x
- 2










0 out of 4 marks (content provider)

Correct Answer: 1
Solution:
Ans: 1





























Q. 10 The last digit of (3P + 2) is :
where P = 34n and n N
1
2
4
5










0 out of 4 marks (content provider)

Correct Answer: 4
Solution:
Ans: 4





























Q. 11 The sum of the binomial coefficients of is equal to 256 . The constant term in the expansion is
1120
2110
1210
none










0 out of 4 marks (content provider)

Correct Answer: 1
Solution:
Ans: 1





























Q. 12 The coefficient of x4 in is :










0 out of 4 marks (content provider)

Correct Answer: 1
Solution:
Ans: 1





























Q. 13 If (1 + x + x2)25 = a0 + a1x + a2x2 + ..... + a50 . x50 then a0 + a2 + a4 + ..... + a50 is :
even
odd & of the form 3n
odd & of the form (3n - 1)
odd & of the form (3n + 1)










0 out of 4 marks (content provider)

Correct Answer: 1
Solution:
Ans: 1





























Q. 14 If the second term of the expansion is 14a5/2 then the value of is :
4
3
12
6










0 out of 4 marks (content provider)

Correct Answer: 1
Solution:
Ans: 1





























Q. 15 If (1 + x) (1 + x + x2) (1 + x + x2 + x3) ...... (1 + x + x2 + x3 + ...... + xn) a0 + a1x + a2x2 + a3x3 + ...... + amxm then has the value equal to
n!
(n + 1) !
(n - 1)!
none










0 out of 4 marks (content provider)

Correct Answer: 2
Solution:
Ans: 2





























Q. 16 The value of 4 {nC1 + 4 . nC2 + 42 . nC3 + ...... + 4n - 1} is :
0
5n + 1
5n
5n - 1










0 out of 4 marks (content provider)

Correct Answer: 4
Solution:
Ans: 4





























Q. 17 In the expansion of (1 + x)43 if the co-efficients of the (2r + 1)th and the (r + 2)th terms are equal, the value of r is :
12
13
14
15










0 out of 4 marks (content provider)

Correct Answer: 3
Solution:
Ans: 3





























Q. 18 The positive value of a so that the co-efficient of x5 is equal to that of x15 in the expansion of is
1
2










0 out of 4 marks (content provider)

Correct Answer: 1
Solution:
Ans: 1





























Q. 19 In the expansion of , the term which does not contain x is :
10C0
10C7
10C4
none










0 out of 4 marks (content provider)

Correct Answer: 3
Solution:
Ans: 3

















































Q. 20 Co-efficient of t in the expansion of, ( + p)m - 1 + ( + p)m - 2 ( + q) + ( + p)m - 3 ( + q)2 + ...... ( + q)m - 1
where - q and p q is :
 
 
 
 
 
 
 
 
 










0 out of 4 marks (content provider)

Correct Answer: 2
Solution:
Ans: 2

6 years ago

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Answers : (3)

										answer soon. pls !!!!!!!!!!!!!! its urgent by VISHWESH RAVI
										
6 years ago
										

Dear Vishesh


1:


first calculate


  r= (n+1)/{1+(x/a)}


here n = 13 , x= 2x = 2*10=20


 a = 5y=5*2=10


so r = 14/3


integer value r=4


so Tr+1 will be the greatest term


i.e   T5


now T5 = 13C4 209 104


please post seperate question in seperate post


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Badiuddin












 

6 years ago
										

thanks a lot sir for the solution.


 


PLEASE PAY ATTENTION TO MY OTHER ASKED QUESTIONS (WITH TITLE PLEASE HELP).


I WILL BE VERY GRATEFUL TO YOU FOR THIS KIND STEP.


 


THANKING YOU,


VISHWESH RAVI

6 years ago

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