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				   Someone please help with these 2 questions.Q. Find inverse of the following functions (solve for x)i)    y = (x^3+5)/(x-3)ii)   y = (x^3-8)/(x^2-4)


6 years ago

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										Ans:(ii)$f(x) = \frac{x^{3}-8}{x^{2}-4}$$f(f^{-1}(x)) = \frac{(f^{-1}(x))^{3}-8}{(f^{-1}(x))^{2}-4}$$(f^{-1}(x))^{3}-x(f^{-1}(x))^{2}+4x-8=0$$f^{-1}(x) = \frac{x-2}{2}\pm \frac{1}{2}\sqrt{x^{2}+4x-12}$Inverse of (i) can not be find in terms of standard mathematical functions.Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago

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 Ajay 4 months ago

Small Mistake in last para posting again..............................................................................................................

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Thankyou so much............................. …......................................................................!

 Anshuman Mohanty 4 months ago

Yes sorry..... . . . .it is not so clear.. ok the values are beta = α + α^2 + α^4 and gamma = α^3 + α^5 + α^7

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Not any people get my answer why. You can no give answer my question I am join this site

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Hello If you want to get the solution quick you should post your question in clear manner. Its not clear what you wnat us to solve, and what does 15 at the end of question means?

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i don’t know how to do this...............................................................................................

 Saravanan 28 days ago

this is the question :: Solve: (sin theta+cosec theta)^2 + (cos theta +sec theta)^2 - (tan^2 theta + cot ^2 theta)

 Naveen Shankar 5 months ago
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Hi Gaurang the question still does not seem to be correct. Can you post the screenshot of question attachment

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