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				   Someone please help with these 2 questions.Q. Find inverse of the following functions (solve for x)i)    y = (x^3+5)/(x-3)ii)   y = (x^3-8)/(x^2-4)


6 years ago

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										Ans:(ii)$f(x) = \frac{x^{3}-8}{x^{2}-4}$$f(f^{-1}(x)) = \frac{(f^{-1}(x))^{3}-8}{(f^{-1}(x))^{2}-4}$$(f^{-1}(x))^{3}-x(f^{-1}(x))^{2}+4x-8=0$$f^{-1}(x) = \frac{x-2}{2}\pm \frac{1}{2}\sqrt{x^{2}+4x-12}$Inverse of (i) can not be find in terms of standard mathematical functions.Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago

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