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`        Find four proportionals such that the sum of the extremes is 21, the sum of the means 19, and sum of the squares of all the four numbers is 442.`
7 years ago

SHAIK AASIF AHAMED
74 Points
```										Hello student,Please find the answer to your question belowLet the numbers be a,b,c,dFrom given a+d=21 and b+c=19a2+b2+c2+d2=442As they are in proportion ad=bcWhen ratio of 2 terms=ratio of 2 other terms they are in proportionSo (a2+d2+2ad)+(b2+c2+2bc)=441+361442+4ad=802ad=90 So ad=bc=90(a-d)2=(a+d)2-4ad=441-360=81So a-d=9 and a+d=21So a=15 d=6Similarly (b-c)2=361-360=1So b-c=1 and b+c=19 So b=10,c=9So Four proportionals are 15,10,9,6
```
3 years ago
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