A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a m/s², the reading of weighing machine is (1) mg (2) m(g-a) (3) m(1-a/g) (4) m(g+a)

Question

Eshan · Answer

Dear student,

Elevator retarding upwards means that it is accelerating downwards with magnitude ‘a’. Hence block experience pseudo force ma upwards. Hence the reading of wieghing machine= m(g-a)

Mohd Suhail Ali · Answer

As lift goes upward net acc. is g+a But here a is retarding so -a should be taken so it will be g-a Hence, N=m(g-a) In kgf the weighing machine reading= m(1-a/g)

nishant narkar · Answer

The normal force tge acts on the blocl is m{g-a} Therefore the weight shown will be m{g-a} please upvote

faz · Answer

here is ur solution for the question . kindly do upvte . this is just formula based and a easy problem

Srishti sharma · Answer

Since it is moving upward , therefore N-mg=ma N= m(g+a) And weighing machine measures Normal reaction not weight if a person . It measures weight in non inertial frame of reference where a = 0 . So option no 4 is correct . Thank you 😊

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A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a m/s², the reading of weighing machine is (1) mg (2) m(g-a) (3) m(1-a/g) (4) m(g+a)

A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a m/s², the reading of weighing machine is
(1) mg
(2) m(g-a)
(3) m(1-a/g)
(4) m(g+a)

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A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a m/s², the reading of weighing machine is (1) mg (2) m(g-a) (3) m(1-a/g) (4) m(g+a)

A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a m/s², the reading of weighing machine is(1) mg(2) m(g-a)(3) m(1-a/g)(4) m(g+a)

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A block of mass m kg is kept on a weighing machine in an elevator. If the elevator is retarding upward by a m/s², the reading of weighing machine is
(1) mg
(2) m(g-a)
(3) m(1-a/g)
(4) m(g+a)