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Asymptotes are the lines whose distance from the curve tends to zero as the point on the curve moves towards infinity along the branch of the curve.
1) If lim x→a f(x) = ∞ or lim x→a f(x) = -∞, then x = a is an asymptote of y = f(x).
2) If lim x→ +∞ f(x) = k or lim x→ -∞ f(x) = k, then y = k is an asymptote of y = f(x).
3) If lim x→-∞ f(x)/x = a2 and lim x→-∞ (f(x) – a2x) = c*, then y = a2x + c* is an asymptote which is inclined towards the left.
4) If lim x→∞ f(x)/x = a1 and lim x→∞ (f(x) – a1x) = c, then y = a1x + c is an asymptote which is inclined towards the right.
1) If all the powers of y in the equation of curve are even, then the curve is symmetrical about the x-axis. For eg: y2 = 4ax
2) Similarly, if all the powers of y in the equation of curve are even, then the curve is symmetrical about the y-axis. For eg: x2 = 4ay
3) If all the powers of x and y in the equation of the curve are even, then the curve is symmetrical both about x as well as y-axis. Eg: x2 + y2 = a2
4) If the equation of the curve remains unchanged on interchanging x and y, then the curve is symmetrical about the line y = x. Eg: x3 + y3 = 3axy
5) If the equation of the curve remains unaltered when x and y are replaced by their negatives i.e. –x and –y respectively, the curve is symmetric in opposite quadrants. Eg: xy = c2
1) To determine the area between curves, first find out the points of intersection of the two curves.
2) If in the domain common to both (i.e. the domain given by the points of intersection) the curves lie above x-axis, then area is
3) If some part of both the curves lies below x-axis then the individual integral must be calculated according to the case in question.
1)In order to obtain area between y = f(x) and the y-axis, the function should first be written in y i.e. y = f(x) must be converted to x = g(y).
2) The integral should then be evaluated as ∫xdy or ∫ydx where integral runs from y1 to y2
3) The area bounded between the y-axis and the curves y = f(x) and y = g(x) can be determined on similar lines by first locating the enclosed region which also helps in identifying the limits.
1) In case, the curve is completely above the x-axis, the resulting area is positive but on the other hand, if it lies completely below the x-axis the area would be negative
2) By, convention only the magnitude is taken into consideration.
3) At times, the curve lies partly above and partly below the x-axis. So in such cases both the areas should be computed separately. Then add up their moduli to get the resultant area.
4) If the curve y = f(x) crosses the x-axis n times when x varies from a to b, then the areas between y = f(x), the x-axis and the lines x= a and x = b is given by A = |A1| + |A2| +……+ |An|.
5) If the curve is symmetrical about the x-axis, or the y-axis, or both, then calculate the area of one symmetrical part and multiply it by the number of symmetrical parts to get the whole area.
1) Let f(x) be a continuous function in (a, b). Then the area bounded by the curve y = f(x), the x-axis and the lines x = a and x = b is given by the formulae A = | ∫ab f(x) dx |, provided f(x) > 0 (or f(x) < 0) ∀ x ∈ (a, b).
2) The area bounded by x = f(y), the y-axis and the lines y = c and y = d is given by A = | ∫cd f(y) dy |, provided f(y) > 0 or f(y) < 0 ∀ y ∈ (c, d)
3) If we have two functions f(x) and g(x) such that f(x) < g(x) ∀ x ∈ [a, b], then the area bounded by the curves y = f(x), y = g(x) and the lines x = a, x = b (a < b) is given by A = | ∫ab [g(x) – f(x)] dx|.
4) If point (0, 0) satisfies the equation, the curve passes through origin.
5) If curve passes through origin, then equate the lowest degree term to zero and get the equation of tangent. In case there are two tangents, the origin is a double point.
6) The points of inflexion can be identified by equation d2y/dx2 = 0 or d2x/dy2 = 0 and solving the resulting equation.
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