# Calculation of percentile, normalization of marks and Composite score

Difference between Percentage & Percentile & calculation of percentile:

**Percentage**: As you all know percentage is a number out of 100.Percentage marks = (Obtained marks / Total marks) ×100

**Percentile:**Percentile score of a candidate reflects the number of students who have scored below that student in his/her own Board ( CBSE, ICSE etc..)

**Example:**In a particular board 4000 candidates appeared in the examination.If a candidate obtained 70 % marks and 2000 students have scored below 70%, then the percentile of that student = (2000×100)/4000 = 50.0

**Normalization of marks**

**Step 1:
**Calculate percentile (P) of all the candidate of board XYZ who are eligible for the JEE (Main) exam, with reference to their board result.

For a Board XYZ

Total Number of the candidates appearing in board exam = 4000

Marks of candidates in Board Exam (m) |
Number of candidates who scored below the candidate (m) |
Percentile Calculation |
Percentile (p |

50% |
1500 |
(1500/4000)×100 |
37.5 |

60% |
1700 |
(1700/4000)×100 |
42.5 |

70% |
2000 |
(2000/4000)×100 |
50.0 |

80% |
2500 |
(2500/4000)×100 |
62.5 |

90% |
3500 |
(3500/4000)×100 |
87.5 |

**Step:2
**In the same way calculate the percentile of all the candidates with reference to their JEE main score.

Let total number of the candidates appearing in JEE (Main) exam = 1000000

JEE(Main) Score (n) |
Number of candidates below the candidate with JEE (Main) score (n) |
Percentile Calculation |
Percentile (p |

75 |
500000 |
(500000/1000000)×100 |
50.0 |

100 |
600000 |
(600000/1000000)×100 |
60.0 |

150 |
700000 |
(700000/1000000)×100 |
70.0 |

200 |
800000 |
(800000/1000000)×100 |
80.0 |

250 |
900000 |
(900000/1000000)×100 |
90.0 |

** ****Step: 3
**Use the value of percentile (P

_{1}) calculated in step 1 (Table 1) and find out the same value of percentile in the table 2 (step 2). The corresponding JEE (Main) score would represent value of B

_{1}.

In our example the percentile of candidate with 70% board marks was 50.

So in table 2, percentile 50.0 represents JEE (Main) score of 75. So, B

_{1}= 75.

**Step:4
**Calculate the percentile of the candidates of the particular board (say XYZ ) who appeared in the JEE main with reference to their JEE main score.

Number of the candidates of board xyz appeared in JEE main = 4000

JEE(Main) Score (n) |
Number of candidates below the candidate with JEE (Main) score (n) |
Percentile Calculation |
Percentile (p |

25 |
1000 |
(1000/4000)×100 |
25.0 |

50 |
1500 |
(1500/4000)×100 |
37.5 |

100 |
2000 |
(2000/4000)×100 |
50.0 |

150 |
3000 |
(3000/4000)×100 |
75.0 |

200 |
3600 |
(3600/4000)×100 |
90.0 |

** ****Step: 5
**Use the value of percentile (P

_{1}) calculated in step 1 (Table 1) and find out the same value in the table 3 (step 4). The corresponding JEE (Main) score would represent value of B

_{2}.

In our example the percentile of candidate with 70% board marks was 50.

So in table 3, percentile 50.0 represents JEE (Main) score of 100. So, B

_{2}= 100

**Step: 6**

B_{final} = 0.5× (B_{1}+B_{2})

In our example:

B _{final} = 0.5× (75 + 100) = 87.5

For admission to CFTIs, it has been decided to use JEE Mains Marks (AO) and the normalized board marks(× B _{final}) in 60:40 ratio.So,

Composite score for drawing the merit list (c ) = 0.6× AO + 0.4× B _{final
}In our example:

c = 0.6× 75 + 0.4× 87.5 = 80.

For getting your estimated rank in IIT JEE you can use our Rank Predictor

This post was published by Aditya Singhal, co-founder of askIITians.

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