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What is the solid angle substended by hemisphere on an external point?

Apoorv Singh , 11 Years ago
Grade 11
anser 1 Answers
Nirmal Singh.
Solid angle dw = dA cos Theta / R2

For hemisphere surface area will be half so the solid angle will be 2 pi at an external point its unit is steradian dw = 2piR2cos 0 / R2 =2 pi steradian ….............................
Last Activity: 11 Years ago
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