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Grade 11Electrostatics

What is the solid angle substended by hemisphere on an external point?

Profile image of Apoorv Singh
11 Years agoGrade 11
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1 Answer

Profile image of Nirmal Singh.
11 Years ago
Solid angle dw = dA cos Theta / R2

For hemisphere surface area will be half so the solid angle will be 2 pi at an external point its unit is steradian dw = 2piR2cos 0 / R2 =2 pi steradian ….............................