What equal charges should be placed on earth and moon to neutralize their gravitation attraction

1Secondary SchoolScience 13 pointsWhat equal charges would have to be placed on earth and moon to neutralize their gravitaional attraction?given, mass of earth =1025 kg ,?AdvertisementAsk for details FollowReport by Jawaidsaman5134 20.06.2017AnswersAlbert01Albert01AceTo neutralize their gravity, the force of repulsion must equal the force of attraction. Universal Gravitational force = (G * m1 * m2) ÷ d^2 G = 6.67 * 10^-11 m1 = mass of earth = 5.98 * 10^24 kg m2 = mass of moon = 7.36 * 10^22 kg d = distance from earth to moon Force caused by charges = (k * q1 * q2) ÷ d^2 k = 9 * 10^9 q1 = charge on earth q2 = charge on moon d = distance from earth to moon Force caused by charges = Universal Gravitational force (k * q1 * q2) ÷ d^2 = (G * m1 * m2) ÷ d^2 Multiply both sides by d^2 (k * q1 * q2) = (G * m1 * m2) Divide both sides by k q1 * q2 = (G * m1 * m2) ÷ k The charges are equal, so q1 * q2 = q^2 q^2 = (G * m1 * m2) ÷ k q = √ (G * m1 * m2 ÷ k) q = √ (6.67 * 10^-11 * 5.98 * 10^24 * 7.36 * 10^22 ÷ 9 * 10^9) q ≈ 3.26 * 10^27 Coulombs

To neutralize their gravity, the force of repulsion must equal the force of attraction. Universal Gravitational force = (G * m1 * m2) ÷ d^2 G = 6.67 * 10^-11 m1 = mass of earth = 5.98 * 10^24 kg m2 = mass of moon = 7.36 * 10^22 kg d = distance from earth to moon Force caused by charges = (k * q1 * q2) ÷ d^2 k = 9 * 10^9 q1 = charge on earth q2 = charge on moon d = distance from earth to moon Force caused by charges = Universal Gravitational force (k * q1 * q2) ÷ d^2 = (G * m1 * m2) ÷ d^2 Multiply both sides by d^2 (k * q1 * q2) = (G * m1 * m2) Divide both sides by k q1 * q2 = (G * m1 * m2) ÷ k The charges are equal, so q1 * q2 = q^2 q^2 = (G * m1 * m2) ÷ k q = √ (G * m1 * m2 ÷ k) q = √ (6.67 * 10^-11 * 5.98 * 10^24 * 7.36 * 10^22 ÷ 9 * 10^9) q ≈ 3.26 * 10^27 Coulombs