What equal charges have to be placed on earth and moon to neutralise their gravitational attraction?
Anuja Fadte , 7 Years ago
Grade 12
2 Answers
Vikas TU
Last Activity: 7 Years ago
For the Equilbrium , Fe = Fg Kq^2/ r^2 = Gm1m2/r^2 q = charge r = distance m1 = mass of earth m2 = mass of moon q^2 = Gm1m2 on substituting the value q = 0.86 x10^!4 C
Rishi Sharma
Last Activity: 4 Years ago
Dear Student, Please find below the solution to your problem.
For the Equilbrium , Fe = Fg Kq^2/ r^2 = Gm1m2/r^2 q = charge r = distance m1 = mass of earth m2 = mass of moon q^2 = Gm1m2 on substituting the value q = 0.86 x 10^!4 C
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