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Grade 12th passElectrostatics

Two smooth spherical non conducting shells A and B each of radius R having uniformly distributed charge Q and -Q on their surfaces are released on a smooth non conducting surface when the distance between their centres is 10R. The mass of A is m and that of B is 2m. What is the speed of A just before it collides with B? (Neglect gravitational interaction)Please help as soon as possible as jee mains is very near. Thankyou

Kriti Srivastava

9 Years agoGrade 12th pass

1 Answer

Pushkar Prateek

9 Years ago

Here we will use two concepts, considering both spheres as a single system.

1. Loss in electrostatic P.E of the system = Gain in K.E. of the system.

2. Since no net external force acts on the system so linear momentum of the system remains conserved.

From 1.

½ m Va²+ ½ 2m Vb^{2 =}KQ²/2R – KQ²/10R (Separation between the spheres just before collision will be 2R)

From 2.

m Va = 2m Vb

Solving above two equations we get

Va = $\sqrt{8KQ^2/15R}$

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