Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

two point charges + q and -2 Q are placed at the vertices B and C of an equilateral triangle ABC of side a is given in the figure obtain the expression for the magnitude and the direction of the resultant electric field at the vertex a due to these two charges

two point charges + q and -2 Q are placed at the vertices B and C of an equilateral triangle ABC of side a is given in the figure obtain the expression for the magnitude and the direction of the resultant electric field at the vertex a due to these two charges

Grade:12

1 Answers

Adarsh
763 Points
3 years ago
electric field due to -2q charge = -2kq/l2 where l = length of sides of equilateral triangle.
electric field due to +q charge = kq/l2 
i hope that you know the direction of electric field . now net resultant electric field= √3.kq/l2-kq/l2.
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free