two point charges + q and -2 Q are placed at the vertices B and C of an equilateral triangle ABC of side a is given in the figure obtain the expression for the magnitude and the direction of the resultant electric field at the vertex a due to these two charges
Anjali , 6 Years ago
Grade 12
1 Answers
Adarsh
Last Activity: 6 Years ago
electric field due to -2q charge = -2kq/l2 where l = length of sides of equilateral triangle.
electric field due to +q charge = kq/l2
i hope that you know the direction of electric field . now net resultant electric field= √3.kq/l2-kq/l2.
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