Two point charge placed at a distance 'r' in air exert a force 'F'. The distance at which they exert same force when placed in certain medium (dielectric constant K) is

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Arun · Answer

Dear student Since the force in both cases is same. So, (1/4*pi* epsilon) ( q1 *q2/r&sup2;) = (1/4*pi* epsilon) (q1*q2/k *r'&sup2;) 1/r&sup2; = 1/k * r'&sup2; r' = r/sqrt(k) Regards Arun (askIITians forum expert)

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Two point charge placed at a distance 'r' in air exert a force 'F'. The distance at which they exert same force when placed in certain medium (dielectric constant K) is

Two point charge placed at a distance 'r' in air exert a force 'F'. The distance at which they exert same force when placed in certain medium (dielectric constant K) is

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