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Grade 12Electrostatics

two particles with positive charges q1 and q2 and equal mass m are separated by a distance d.the lower one is at a distance h from ground and takes time t to fall and looses its charge after falling. find the time taken by upper charge to fall?

varun porwal

12 Years agoGrade 12

1 Answer

Arun Kumar

12 Years ago

Height of upper =h+d

lower =d

$g_{eff\,for\,lower}=(kq_1q_2/(d+x)^2+g) (-j)\\ g_{eff\,for\,upper\,until\, time \,t}=(-kq_1q_2/(d+x)^2+g) (-j) \\\\ apply\,vdv/ds=a\\ assuming\,v=0 \,at \,start\\ then\\ apply dx/dt=v \\\for \,both \,particle.$

with proper limits.

Thanks & Regards

Arun Kumar

IIT Delhi

Askiitians Faculty

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