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Applying conservation of momentam bw initial and final stage
Pi = 0
Pf = mv1 +mv2
Pf = Pi
v1 = -v2..........1
Now applying energy conservation bw two points
KEi + (P.E)i = KEf + (P.E)f
(mv1^2 -mv2^2)/2 =kq^2(2/r -1/r )
mv1^2=154/10
v1=53.66m/s=-v2
Regards
Arun (askIITians forum expert)
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