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Two parallel large thin metal sheets have equal surface charge densities of opposite signs. The electric field between these sheets is..( charge per unit length= 26.4 * 10raised to the power -12 c/m2...Please provide answer with solution

VIDYARANI SINGADI , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 6 Years ago

Electric field intensity between two parallel sheets have equal surface charge densities of opposite sign is given by E = σ/ε₀
Here given, σ = 26.4 × 10⁻¹²C/m² 
and ε₀ = 8.875 × 10⁻¹² C²/Nm² 
So, Electric field intensity between sheets = 26.4 × 10⁻¹²/8.875 × 10⁻¹² ≈ 3 N/C 
Hence, answer is 3N/C
 
 

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