Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Two parallel large thin metal sheets have equal surface charge densities of opposite signs. The electric field between these sheets is.. ( charge per unit length= 26.4 * 10raised to the power -12 c/m2... Please provide answer with solution

Two parallel large thin metal sheets have equal surface charge densities of opposite signs. The electric field between these sheets is..
( charge per unit length= 26.4 * 10raised to the power -12 c/m2...
Please provide answer with solution

Grade:12th pass

1 Answers

Arun
25763 Points
2 years ago
Electric field intensity between two parallel sheets have equal surface charge densities of opposite sign is given by E = σ/ε₀
Here given, σ = 26.4 × 10⁻¹²C/m² 
and ε₀ = 8.875 × 10⁻¹² C²/Nm² 
So, Electric field intensity between sheets = 26.4 × 10⁻¹²/8.875 × 10⁻¹² ≈ 3 N/C 
Hence, answer is 3N/C
 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free