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Two identical particles of mass m carry a charge q each. Initially one is at rest on a horizontal plane and the other is projected towards the first from a large distance with v velocity find closest distance of approach

Two identical particles of mass m carry a charge q each. Initially one is at rest on a horizontal plane and the other is projected towards the first from a large distance with v velocity find closest distance of approach

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Grade:12th pass

1 Answers

Arun
25763 Points
4 years ago
 

As there is no external force present hence the system's total energy will remain constant. So, the initial KE will be totally converted to the system's PE when they are closest to each other. Hence from there we get,

 

(1/4∏ε)Q²/R=(1/2)mv²

 

R=Q²/(2∏εv²)

 

answer which is given in your question is wrong.

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