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Two identical particles of mass m carry a charge q each. Initially one is at rest on a horizontal plane and the other is projected towards the first from a large distance with v velocity find closest distance of approach

Vishal , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 7 Years ago

 

As there is no external force present hence the system's total energy will remain constant. So, the initial KE will be totally converted to the system's PE when they are closest to each other. Hence from there we get,

 

(1/4∏ε)Q²/R=(1/2)mv²

 

R=Q²/(2∏εv²)

 

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