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Grade 12th passElectrostatics

Two identical particles of mass m carry a charge q each. Initially one is at rest on a horizontal plane and the other is projected towards the first from a large distance with v velocity find closest distance of approach

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Vishal

8 Years agoGrade 12th pass

1 Answer

Arun

8 Years ago

As there is no external force present hence the system's total energy will remain constant. So, the initial KE will be totally converted to the system's PE when they are closest to each other. Hence from there we get,

(1/4∏ε)Q²/R=(1/2)mv²

R=Q²/(2∏εv²)

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